RF EXPO INFO

FCC ID: TUVDS-8333

RF Exposure Info

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FCCID_4471996

RF Exposure evaluation

According to 447498 D01 General RF Exposure Guidance v05
The 1-g and 10-g SAR test exclusion thresholds for 100 MHz to 6 GHz at
test separation distances ≤ 50 mm are determined by:
[(max. power of channel, including tune-up tolerance, mW)/(min. test
separation distance, mm)] ·[√f(GHz)] ≤ 3.0 for 1-g SAR and ≤ 7.5 for
10-g extremity SAR, where
f(GHz) is the RF channel transmit frequency in GHz
Power and distance are rounded to the nearest mW and mm before
calculation
The result is rounded to one decimal place for comparison

eirp = pt x gt = (EXd)2/30
where:
pt = transmitter output power in watts,
gt = numeric gain of the transmitting antenna (unitless),
E = electric field strength in V/m, --- 10((dBuV/m)/20)/106
d = measurement distance in meters (m)---3m
So pt = (EXd)2/30 x gt

Field strength = 88.06dBuV/m @3m
Ant gain =0dBi ;so Ant numeric gain= 1

So pt={ [10(88.06 /20)/106 x3]2/30x1 }x1000 mW =0.19mW
So (0.19 mW/5mm)x √2.468GHz = 0.06 <3

Then SAR evaluation is not required

Document Created: 2019-09-29 11:22:02
Document Modified: 2019-09-29 11:22:02

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