RF exposure letter

FCC ID: 2AOKM-TY6

RF Exposure Info

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FCCID_4300585

RF Exposure evaluation

According to 447498 D01 General RF Exposure Guidance v05
The 1-g and 10-g SAR test exclusion thresholds for 100 MHz to 6 GHz at
test separation distances≤ 50 mm are determined by:
[(max. power of channel, including tune-up tolerance, mW)/(min. test
separation distance, mm)] ·[√f(GHz)] ≤ 3.0 for 1-g SAR and ≤ 7.5 for
10-g extremity SAR, where
f(GHz) is the RF channel transmit frequency in GHz
 Power and distance are rounded to the nearest mW and mm before
calculation
 The result is rounded to one decimal place for comparison

eirp = pt x gt = (EXd)2/30
where:
pt = transmitter output power in watts,
gt = numeric gain of the transmitting antenna (unitless),
E = electric field strength in V/m, --- 10((dBuV/m)/20)/106
d = measurement distance in meters (m)---3m
Sopt = (EXd)2/30 x gt

Ant gain= 0dBi ;so Ant numeric gain= 1

Field strength = 70.49 dBuV/m @3m
So Pt={ [10(70.49 /20)
/106 x3]2/30x1 }x1000 mW = 0.003366 mW

So ( 0.003366 mW/5mm)x √0.3122 GHz = 0.000376 < 3

Then SAR evaluation is not required

Document Created: 2019-05-31 00:22:47
Document Modified: 2019-05-31 00:22:47

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