RF exposure letter

FCC ID: 2AOKM-HDODY

RF Exposure Info

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FCCID_4316409

                         RF Exposure evaluation


According to 447498 D01 General RF Exposure Guidance v05
The 1-g and 10-g SAR test exclusion thresholds for 100 MHz to 6 GHz at
test separation distances≤ 50 mm are determined by:
[(max. power of channel, including tune-up tolerance, mW)/(min. test
separation distance, mm)] ·[√f(GHz)] ≤ 3.0 for 1-g SAR and ≤ 7.5 for
10-g extremity SAR, where
 f(GHz) is the RF channel transmit frequency in GHz
   Power and distance are rounded to the nearest mW and mm before
calculation
  The result is rounded to one decimal place for comparison



eirp = pt x gt = (EXd)2/30
where:
pt = transmitter output power in watts,
gt = numeric gain of the transmitting antenna (unitless),
E = electric field strength in V/m, ---     10((dBuV/m)/20)/106
d = measurement distance in meters (m)---3m
Sopt = (EXd)2/30 x gt


Ant gain=0dBi ;so Ant numeric gain=1


Field strength = 65.24 dBuV/m @3m
So Pt={ [10(65.24/20)/106 x3]2/30x1 }x1000 mW = 0.003 mW


So ( 0.003 mW/5mm)x √0.31385 GHz = 0.000336 < 3



Then SAR evaluation is not required



Document Created: 2019-06-13 16:51:27
Document Modified: 2019-06-13 16:51:27

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