RF Exposure

FCC ID: 2AEW6-TE-P20

RF Exposure Info

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FCCID_3122663

RF Exposure evaluation According to 447498 D01 General RF Exposure Guidance v05 The 1-g and 10-g SAR test exclusion thresholds for 100 MHz to 6 GHz at test separation distances ≤ 50 mm are determined by: [(max. power of channel, including tune-up tolerance, mW)/(min. test separation distance, mm)] ·[√f(GHz)] ≤ 3.0 for 1-g SAR and ≤ 7.5 for 10-g extremity SAR, where f(GHz) is the RF channel transmit frequency in GHz Power and distance are rounded to the nearest mW and mm before calculation The result is rounded to one decimal place for comparison eirp = pt x gt = (EXd)2/30 where: pt = transmitter output power in watts, gt = numeric gain of the transmitting antenna (unitless), E = electric field strength in V/m, --- 10((dBuV/m)/20)/106 d = measurement distance in meters (m)---3m So pt = (EXd)2/30 x gt Ant gain=0 dBi ;so Ant numeric gain=1 Field strength = 96.78 dBuV/m @3m So Pt={ [10(96.78 /20)/106 x3]2/30x1 }x1000 mW = 1.5 mW So ( 1.5 mW/5mm)x √2.402 GHz = 0.47 < 3 Then SAR evaluation is not required


Document Created: 2016-09-05 08:44:46
Document Modified: 2016-09-05 08:44:46
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