RF Exposure Info

FCC ID: 2AD5KMWB300

RF Exposure Info

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FCCID_4349585

FCC ID: 2AD5KMWB300 According to KDB 447498 D01 General RF Exposure Guidance At 100 ㎒ to 6 ㎓ and for test separation distances ≤ 50 ㎜, the SAR test exclusion threshold is determined according to the following [(max. power of channel, including tune-up tolerance, ㎽) / (min. test separation distance, ㎜)] x [√f(㎓)] ≤ 3.0 1. SAR test exclusion threshold Frequency: 2 480 ㎒ (min. separation distances = 0 ㎜) Calculation value: 2 (㎽) / 5 (㎜) x √ 2.480 = 0.630 So, Calculation value ≤ 3.0 Remark; -Max. conducted power (㎽): maximum tolerance power of EUT (2 ㏈m) -Max. conducted power 2 (㎽) was calculated. - When the minimum test separation distance is < 5 ㎜, a distance of 5 ㎜ is applied to determine SAR test exclusion. 2. SAR test exclusion threshold Frequency : 433.92 ㎒ (min. separation distances = 0 ㎜) Calculation value: 1 (㎽) / 5 (㎜) x √ 0.433 92 = 0.132 So, Calculation value ≤ 3.0 Remark: -Max. Radiated field strength 68.86 (㏈㎶): Max. E.I.R.P. of EUT (-26.37 ㏈m) -Max. E.I.R.P. 0.002 (㎽) is less than 1 (㎽), so 1 (㎽) was calculated. -When the minimum test separation distance is < 5 ㎜, a distance of 5 ㎜ is applied to determine SAR test exclusion. 3. Simultaneous transmission SAR test exclusion considerations. [(max. power of channel, including tune-up tolerance, ㎽) / (min. test separation distance, ㎜)] x [√f(㎓) / χ ] where χ = 7.5 for 1-g SAR Bluetooth Low Energy 2 (㎽) / 5 (㎜) x √ 2.480 / 7.5 = 0.084 Transmitter 1 (㎽) / 5 (㎜) x √ 0.433 92 / 7.5 = 0.018 Confirm the sum result of individual SAR estimation is < 1.6; Bluetooth Low Energy + Transmitter: 0.084 + 0.018 = 0.102 < 1.6 4. Conclusion: No SAR is required.


Document Created: 2019-06-27 15:25:33
Document Modified: 2019-06-27 15:25:33
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